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likoan [24]
3 years ago
9

Which value is equivalent to

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

No one.

Step-by-step explanation:

\frac{(7^0)^3}{[tex]\\\frac{\frac{(7*3*2)^2}{(7*5)(7^0)^3}}{5^{-3} *5^ {-9}} = \frac{\frac{7^2*3^2*2^2}{(7*5)(1)}}{5^{-12}} =\frac{\frac{7*3^2*2^2}{5}}{5^{-12}} =\frac{7*3^2*2^2}{5^{-11}}= 7*3^2*2^2*{5^{11}}=1.23* 10^{10}} = \frac{1}{5^ {-12}} = 5^ {12}[/tex]

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Answer:

The required relation is,

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Step-by-step explanation:

We know that for a certain amount of dry gas when the pressure is kept constant it's volume V and temperature T is related by the function,

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So, in that case rate of change of volume(V) with respect to time (t),

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where \frac {dT}{dt}  is equal to rate of change of temperature (T) with  respect to time (t) and c is the constant stated before.

So, the required relation is,

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