Question

Which value is equivalent to

Answer 1

Answer:

No one.

Step-by-step explanation:

$\frac{(7^0)^3}{[tex]\\\frac{\frac{(7*3*2)^2}{(7*5)(7^0)^3}}{5^{-3} *5^ {-9}} = \frac{\frac{7^2*3^2*2^2}{(7*5)(1)}}{5^{-12}} =\frac{\frac{7*3^2*2^2}{5}}{5^{-12}} =\frac{7*3^2*2^2}{5^{-11}}= 7*3^2*2^2*{5^{11}}=1.23* 10^{10}$} = \frac{1}{5^ {-12}} = 5^ {12}[/tex]