The expressions with radicals which are variables and numbers raised to a fractional indices are simplified as follows.
13. √(9·x) = 3·√x
14. √(4·y) = 2·√y
15. √(8·x²) = 2·x·√2
16. √(9·x²) = 3·x
17. √(3·x²) = x·√3
18. √(5·y²) = y·√5
19. √(13·x²) = x·√(13)
20. √(29·y²) = y·√(29)
21. √(64·y²) = 8·y
22. √(125·a²) = 5·a·√5
23. ∛(16) = 2·∛2
24. √(50·a²·b) = 5·a·√(2·b)
<h3>What are radicals expressions?</h3>
A radical expression is one that contains the radical (square root or nth root) sign, √.
13. √(9·x)
√(9·x) = √(3²·x) = 3·√x
14. √(4·y)
√(4·y) = √(2²·y) = 2·√y
15. √(8·x²)
√(8·x²) = √(4 × 2·x²) = √(2² × 2·x²)
√(2² × 2·x²) = √(2²·x² × 2) = 2·x·√2
16. √(9·x²)
√(9·x²) = √(3²·x²) = 3·x
17. √(3·x²)
18. √(5·y²)
√5 × √(y²) = √5 × y = y·√5
19. √(13·x²)
√(13·x²) = √(13) × √x² = √(13) × x = x·√(13)
20. √(29·y²)
√(29·y²) = √(29) × √(y²) = √(29) × y = y·√(29)
21. √(64·y²)
√(64·y²) = √(8²·y²) = √(8²) × √(y²) = 8 × y = 8·y
22. √(125·a²)
√(125·a²) = √(25 × 5 × a²) = √(25) × √5 × √(a²) = 5 × √5 × a
5 × √5 × a = 5·a·√5
23. ∛(16)
∛(16) = ∛(16) = ∛(8 × 2) = ∛(2³ × 2) = 2·∛2
24. √(50·a²·b)
√(50·a²·b) = √(25 × 2 × a² × b) = √(5² × 2 × a² × b) = √(5² × a² × 2 × b)
√((5² × a²) × 2 × b) = 5·a·√(2·b)
Learn more about simplifying expressions with radicals here:
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Answer:
Therefore, Sara’s current age (5 years later) is 19 years old.
Step-by-step explanation:
Let xx be Sara’s age five years ago. Therefore, Sara’s aunt’s age 5 years ago is 4x4x.
The difference in their ages is a constant, no matter how many years have gone by. (Can you see why?)
4x−x=42
3x=42
x=42/3
x=14
14+5=19
Therefore, Sara’s current age (5 years later) is 19 years old.
We have the rational expression
; to simplify it, we are going to try to find a common factor in the numerator, and, if we are luckily, that common factor will get rid of the denominator
.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable
, and the least exponent of that variable is 1, so
will be the other part of our common factor. Lets put the two parts of our common factor together to get
.
Now that we have our common factor, we can rewrite our numerator as follows:
We are luckily, we have
in both numerator and denominator, so we can cancel those out:
We can conclude that the simplified version of our rational function is
.
Hello! Draw a hundred (I know, it's tedious!) circles. Make a giant bracket around them all and label it "One Whole". Then color in 51 of those circles.
I hope this helps!
You have two choices.
The minimum possible cost to operate your bat factory for a day is $390,
and there are two quantities of bats that both cost that much.
One possibility:
Produce no bats at all per day. Zero. Nada. None.
Cost = 0.06(0)² - 7.2(0) + 390 = $390 per day.
The other choice:
Produce 120 bats per day.
Cost = 0.06(120²) - 7.2(120) + 390
= 0.06(14,400) - 7.2(120) + 390
= 864 - 864 + 390
= $390 per day.
If you produce any other number of bats in a day ... more than zero
but not 120 ... then it will cost you more than $390 to operate the factory
that day.
