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Darina [25.2K]
4 years ago
11

In a batch of 890 calculators, 12 were found to be defective. What is the probability that a calculator chosen at random will be

defective? Write the probability as a percent. Round to the nearest thence of a percent of necessary.
Mathematics
2 answers:
scoray [572]4 years ago
3 0

Answer:

<em>1.3%</em>

When entered into a calculator, 12/890 (the chance of a given calculator being defective) = 0.01348...

As a percent this is 100*0.01348% = 1.348%, and to the nearest tenth, 1.3%

NARA [144]4 years ago
3 0

Answer:

1.3%

Step-by-step explanation:

First set this up as the proportion

Is over of equals percent over 100

We put x as the percent because that's what were trying to figure out

is/of = x/100

Since there are only two numbers in the problem it will be easier to find out what numbers are the is and the of.

The problems says 12 out of 890 calculators are defective. So 890 will be our of and 12 will be the is

So 12/890 = x/100

Now we have to do Cross Product Property

So 12*100 = 1200

890*x = 890x

890x = 1200

Then you have to solve for x by dividing 1200 by 890, which is 1.3483%

Now round 1.3483% to the tenth of a percent

1.3%

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Find the missing length indicated?
kondor19780726 [428]

Answer:

D. 15

Step-by-step explanation:

Let the missing length be represented as x.

Thus:

(24 - x)/12 = x/20 => angle bisector theorem

Cross multiply

20(24 - x) = x(12)

480 - 20x = 12x

480 - 20x + 20x = 12x + 20x

480 = 32x

480/32 = 32x/32

15 = x

Missing length = x = 15

6 0
3 years ago
The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan
kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points (x_1, y_1) and (x_2,y_2) is,

d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Length of PQ = \sqrt{(1-1)^2+(2-6)^2}

PQ = 4

Length of PR = \sqrt{(1+4)^2+(2-2)^2}

PR = 5

Length of QR = \sqrt{(1+4)^2+(6-2)^2}

QR = \sqrt{25+16}

     = \sqrt{41}

     = 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

                                                                       = 4 + 6.4 + 5

                                                                       = 15.4 yards

4 0
4 years ago
What is -23/6 - 7/3<br>A-37/6<br>B-30/9<br>C-16/6<br>D37/6​
8_murik_8 [283]

Answer:

A

Step-by-step explanation:

i solved it

7 0
3 years ago
Can you the nearest hundredth to 1.2983?
ozzi
I think so it’s 1.30
3 0
3 years ago
Read 2 more answers
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
3 years ago
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