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Black_prince [1.1K]
2 years ago
14

You purchase 2 action figures per week. You have 48 action figures, which is 75% of the total number of action figures you need

to complete your collection. How many weeks until your collection is complete?
Mathematics
1 answer:
LiRa [457]2 years ago
3 0

Answer:

Step-by-step explanation:

Let the total number of action figures = x

75% of x = 48

\dfrac{75}{100}*x=48\\\\Multiply \ by \ 100\\\\75*x =48*100\\\\Divide  \ by \ 75\\\\x=\dfrac{48*100}{75}\\\\\\x=16*4\\\\x= 64

Remaining action figures need to be collected = total figures - number of action figures I have

= 64 - 48 = 16

Number of weeks = 16 ÷ 2 = 8

It will take 8 weeks to collect 16 action figures.

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Answer: $754.94

Step-by-step explanation:

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3 years ago
What theorem states that if two sides and the included angle of one triangle are congruent to the corresponding parts of another
lianna [129]

The given statement is proved by side-angle-side (SAS) theorem.

Yes, if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle the triangles are congruent.

The statement is proved by SAS theorem

<u>Side-Angle-Side (SAS) theorem: </u>

The triangles are congruent if two sides and the included angle of one triangle are equivalent to two sides and the included angle of another triangle.

Hence, The given statement is proved by side-angle-side (SAS) theorem.

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1 year ago
A scooter travels 30 feet in 2 seconds at a constant speed.
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Answer:

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7 0
3 years ago
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

3 0
3 years ago
Veda solves the following system of linear equations by eliminations. What is the vale of x in the solution of the system of equ
kupik [55]

Answer:

x = -1, y = 1

Step-by-step explanation:

6 + 4x - 2y = 0 (1)

-3 - 7y = 10x (2)

From (1)

6 + 4x - 2y = 0 (1)

4x - 2y = -6 (3)

From (2)

-3 - 7y = 10x (2)

10x + 7y = -3 (4)

4x - 2y = -6 (3)

10x + 7y = -3 (4)

Using elimination method

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x = -4/4

x = -1

x = -1, y = 1

The value of x in the equation is -1

4 0
3 years ago
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