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Serjik [45]
3 years ago
9

What is the speed of a wave that has a frequency of 200 Hz and a

Physics
1 answer:
Luba_88 [7]3 years ago
8 0
The wave speed to this question is 400 meters
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How are joules measured ?
saw5 [17]

Answer:You can calculate it by finding the amount of work exerted.

Explanation:

4 0
3 years ago
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White light is an _____ mixture of all the colors.
Luba_88 [7]

Answer:

White light is a combination of all colors in the color spectrum.

Explanation:

It has all the colors of the rainbow. Combining primary colors of light like red, blue, and green creates secondary colors: yellow, cyan, and magenta

6 0
2 years ago
Assume that a pendulum used to drive a grandfather clock has a length L0=1.00m and a mass M at temperature T=20.00°C. It can be
Sedaia [141]

Answer:

The period will change a 0,036 % relative to its initial state

Explanation:

When the rod expands by heat its moment of inertia increases, but since there was no applied rotational force to the pendulum , the angular momentum remains constant. In other words:

ζ= Δ(Iω)/Δt, where ζ is the applied torque, I is moment of inertia, ω is angular velocity and t is time.

since there was no torque ( no rotational force applied)

ζ=0 → Δ(Iω)=0 → I₂ω₂ -I₁ω₁ = 0 → I₁ω₁ = I₂ω₂

thus

I₂/I₁ =ω₁/ω₂ , (2) represents final state and (1) initial state

we know also that ω=2π/T , where T is the period of the pendulum

I₂/I₁ =ω₁/ω₂ = (2π/T₁)/(2π/T₂)= T₂/T₁

Therefore to calculate the change in the period we have to calculate the moments of inertia. Looking at tables, can be found that the moment of inertia of a rod that rotates around an end is

I = 1/3 ML²

Therefore since the mass M is the same before and after the expansion

I₁ = 1/3 ML₁² , I₂ = 1/3 ML₂²  → I₂/I₁ = (1/3 ML₂²)/(1/3 ML₁²)= L₂²/L₁²= (L₂/L₁)²

since

L₂= L₁ (1+αΔT) , L₂/L₁=1+αΔT  , where ΔT is the change in temperature

now putting all together

T₂/T₁=I₂/I₁=(L₂/L₁)² = (1+αΔT) ²

finally

%change in period =(T₂-T₁)/T₁ = T₂/T₁ - 1 = (1+αΔT) ² -1

%change in period =(1+αΔT) ² -1 =[ 1+18×10⁻⁶ °C⁻¹ *10 °C]² -1 = 3,6 ×10⁻⁴ = 3,6 ×10⁻² %  = 0,036 %

4 0
3 years ago
0.16 mol of argon gas is admitted to an evacuated 70 cm^3 container at 30°C. The gas then undergoes an isothermal expansion to a
Semmy [17]

Answer:

The final pressure of the gas is 9.94 atm.

Explanation:

Given that,

Weight of argon = 0.16 mol

Initial volume = 70 cm³

Angle = 30°C

Final volume = 400 cm³

We need to calculate the initial pressure of gas

Using equation of ideal gas

PV=nRT

P_{i}=\dfrac{nRT}{V}

Where, P = pressure

R = gas constant

T = temperature

Put the value in the equation

P_{i}=\dfrac{0.16\times8.314\times(30+273)}{70\times10^{-6}}

P_{i}=5.75\times10^{6}\ Pa

P_{i}=56.827\ atm

We need to calculate the final temperature

Using relation pressure and volume

P_{2}=\dfrac{P_{1}V_{1}}{V_{2}}

P_{2}=\dfrac{56.827\times70}{400}

P_{2}=9.94\ atm

Hence, The final pressure of the gas is 9.94 atm.

3 0
3 years ago
Please help me I need this for a test
Marysya12 [62]

Answer:

Explanation:

Lol thats big tufffffffffvffffffftg

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8 0
3 years ago
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