Answer:
yes they can
Step-by-step explanation:
Answer:
y=x, x-axis, y=x, y-axis
Explanation:
Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.
Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.
However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.
<span>First find the area of the field
A=WL
A=(110m)(60m)
A=6,600m^2
Now turn the cm into m
becouse 100cm^3=1m^3
660,000,000cm^3=6,600,000m^3
Now find out how many times you can cover the filled
6,600,000m^3/6,600m^2=100m
So it will be 100m thick.
P.S. I'm assuming you meant you jest forgot the m for 110m.</span>
I like to solve these by graphing, so if you graph both of these functions (as shown in the picture below), you look for the intersection between the two graphs, which in this case is
(-2,6).
Answer:
2
Step-by-step explanation: