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Paha777 [63]
3 years ago
8

Solve the proportion ? : 32 = 9 : 4 for the unknown. a72b48c36d18

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

72 is the answer

Step-by-step explanation:

x : 32 = 9 :4

\frac{x}{32} = \frac{9}{4}

cross multiplying

∴ 4 × x = 32 × 9

  4 x = 288

Therefore x = \frac{288}{4}

      x = 72

zzz [600]3 years ago
4 0

Answer:

x : 32 = 9 : 4

4x = 288

x = 72

Step-by-step explanation:

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5/8 cm

Step-by-step explanation:

5/2*3/4=15/8

15/8*1/3=15/24=5/8

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A water tank holds 648 gallons but is leaking at a rate of 4 gallons per week. A second water tank holds 864 gallons but is leak
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X - 2y &lt; 2<br> graph the inequality
Korvikt [17]

Answer:

y > 1/2x - 1

First, draw the dashed line y = 1/2x - 1 (slope intercept ; y = mx + b).

Start at -1 on the y-axis, and continue going 2 units to the right, and 1 unit up for the right side of the graph.

Then starting at -1 on the y-axis, continue going 2 units to the left, and 1 unit down for the left side of the graph.

Explanation:

Convert standard form (Ax + By = C) by isolating y from the rest of the equation.

Ax + By = C → y = -Ax/B + C/B → y = mx + b.

Given a standard form equation in inequality form,

x - 2y < 2.

Set it to slope-intercept as an inequality to find the slope and y-intercept.

When negating (making opposite) a variable, you flip the inequality.

x - 2y < 2 → x - 2y - x < 2 - x → -2y < -x + 2 → 2y > x - 2 → <u>y > 1/2x - 1</u><u>.</u>

3 0
3 years ago
What fractional part of 1 pound is an ounce?
bezimeni [28]
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3 0
3 years ago
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
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