Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
The value of k is -11
Step-by-step explanation:
If (x+2) is a factor of x3 − 6x2 + kx + 10:
Then,
f(x)=x3 − 6x2 + kx + 10
f(-2)=0
f(-2)=(-2)³-6(-2)²+k(-2)+10=0
f(-2)= -8-6(4)-2k+10=0
f(-2)= -8-24-2k+10=0
Solve the like terms:
f(-2)=-2k-22=0
f(-2)=-2k=0+22
-2k=22
k=22/-2
k=-11
Hence the value of k is -11....
It should be 121, or +4 or -4 from that. But I am pretty sure it is 121
Answer:
41,600yd's is the area....
Answer:
P(x)=-2x^2+34x+98
The cost function is given by c(x)=21x-98
And the revenue function is given by r(x)=55x-2x^2
The profit function is the difference of revenue function and the cost function. Mathematically, we can write
p(x)=r(x)-c(x)
Substituting the values, we get
p(x)=55x-2x^2-(21x-98)
p(x)=-2x^2 + 34x = 98
Therefore, the profit function is
p(x) = -2x^2 + 34x + 98
Step-by-step explanation:
