Question

LOOK AT CHART BEFORE THE BULLET PART:

Answer 1

Answer:

1st blank: $\text{Slope(m)}=-\frac{3}{4}$

2nd blank: $\text{y-intercept}=399$

3rd blank: Slope-intercept form:$y=-\frac{3}{4}x+399$

Step-by-step explanation:

Let x be the number of sandwiches and y be the number of wraps.

We have been given a chart of values, which represents Sal's total profit on lunch specials for two months. We are asked to fill in the empty boxes.

We have been given that Sal gets a profit of $3 after selling each sandwich, so Sal's profit after selling x sandwiches will be 3x.

As each wrap gives a profit of $4, So Sal's profit after selling y wraps will 4y.

Since Sal’s total profit on lunch specials for next month is $1596. We can represent this information in an equation as:

$3x+4y=1596$

We can see that our equation is in standard form, so let us convert it in slope-intercept form of equation.

Since we know that equation of a line in slope-intercept form is: $y=mx+b$, where,

m = Slope of line,

b = y-intercept or initial value.

Let us subtract 3x from both sides of our equation.

$3x-3x+4y=1596-3x$

$4y=1596-3x$

Let us divide both sides of our equation by 4.

$\frac{4y}{4}=\frac{1596-3x}{4}$

$y=\frac{1596}{4}-\fraxc{3x}{4}$

$y=399-\frac{3}{4}x$

$y=-\frac{3}{4}x+399$

Therefore, equation $y=-\frac{3}{4}x+399$ represents the Sal's total profit for 2nd month in slope-intercept form of equation.

Upon comparing our equation with slope-intercept form of equation we can see that slope of our line is $-\frac{3}{4}$ and y-intercept is 399.