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Nimfa-mama [501]
3 years ago
8

I need help finding b

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0
Tan^-1 = 72.81° is your answer, use basic SOHCAHTOA functions
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If 25 articles cost $43.75 how much does each cost?​
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$1.75

Step-by-step explanation:

I had this question and got it right!

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Which graph represents the inequality x ≥ 23?
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D

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Please help with math
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I did some research, and I think it's the first one. PLEASE CORRECT ME IF I'M WRONG!!
Here's why, because the first segment extends from 0 to 1. So, x has to be 0 or larger, but less than 1 or 1.
5 0
3 years ago
It took 20,000 workers to build the Taj Mahal in 20 years. How many workers would be required to build it in 10 years?
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Answer:

40,000 workers

Step-by-step explanation:

This question deals with simple rates proportion.

If it takes 20 years for X workers to complete a job,

if we double the amount of workers, we will take half the time.

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4 0
3 years ago
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Se tienen 16 maquinas cuyo rendimiento es del 90% y produce 4800 articulos en 6 dias trabajando 10horas diarias. Si se desea pro
cupoosta [38]

Answer:

5 máquinas.

Step-by-step explanation:

Sabemos que con 16 máquinas, cada una con un rendimiento del 90%, se producen 4800 artículos en 6 días trabajando 10 horas diarias.

Primero extraigamos toda la información útil de esto.

Sea R la velocidad con la que trabaja una máquina con un rendimiento del 100%.

Entonces nuestras máquinas van a trabajar a:

(90%/100%)*R = 0.9*R

16 máquinas juntas trabajaran en total a 16 veces esa cantidad, o:

16*0.9*R

Luego también sabemos que las máquinas trabajan 10 horas al día por 6 días, es decir, trabajan un total de:

6*10h = 60h

60 horas.

Entonces podemos plantear la ecuación:

(16*0.9*R)*60h = 4800 artículos.

Ahora podemos despejar el valor de R.

R = (4800 artículos)/(16*0.9*60 horas) = 5.556 artículos/hora

Ahora:

Se desea producir 1200 artículos.

En 8 días trabajando 9 horas al día, es decir en:

8*9h = 72 horas

Con N máquinas al 60%.

Cada máquina al 60% trabajara con una velocidad de:

0.6*R

N máquinas entonces trabajaran en conjunto a:

N*(0.6*R)

Con la información que se nos da, podemos plantear la ecuación:

N*(0.6*R)*72horas = 1200 artículos.

Queremos resolver esto para N, el número de máquinas, entonces aislamos N

N = (1200 artículos)/((0.6*R)*72horas)

Reemplazando el valor de R, que es 5.556 artículos/hora

N = (1200 artículos)/((0.6*5.556 artículos/hora)*72horas) = 5

Se necesitaran 5 máquinas.

5 0
3 years ago
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