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3 years ago

My daughter needs help with homework

Mathematics

1 answer:

Inessa [10]3 years ago

7 0

Matt is wrong because 5-1=4 and 5-1 1/4= 3 3/4

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Car insurance companies want to keep track of the average cost per claim. The current data in use for Auto Insurance R Us is an

eduard

I just took the test, the answer is 5%.

5 0

3 years ago

Read 2 more answers

Write the equation of the line that passes through the points (- 5, 1) and (2, 0) . Put your answer in fully reduced slope inter

Doss [256]

Answer:

y=-1/7x + 12/7

Step-by-step explanation:

Start by finding the slope

m=(1-0)/(-5-2)

m=-1/7

next plug the slope and the point (-5,1) into point slope formula

y-y1=m(x-x1)

y1=1

x1= -5

m=-1/7

y- 1 = -1/7(x - -5)

y-1=-1/7(x+5)

Distribute -1/7 first

y- 1=-1/7x + 5/7

Add 1 on both sides, but since its a fraction add 7/7

y=-1/7x + (5/7+7/7)

y=-1/7x+12/7

3 0

3 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

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3 years ago

What are the next three terms in the sequence 11,18,25,32

Marat540 [252]

39 it's an arithmetic sequence in which the common difference is +7

8 0

3 years ago

Read 2 more answers

Write the equation of the line in point-slope form that goes through the points (0, 1) and (2, 7)

laiz [17]

Answer:

point - slope form

y - 1 = 3 (x-0)

Step-by-step explanation:

step(i):-

Given points are (0,1) and (2,7)

The slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

$m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{7-1}{2-0} = \frac{6}{2} = 3$

m =3

Step(ii):-

point -slope form

y - y₁ = m(x-x₁)

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3

y - 1 = 3 (x-0)

y -1 = 3x

3x - y +1=0

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3 is 3x -y +1=0

4 0

2 years ago