Answer:
The graph should be stretched rather than become narrower.
Step-by-step explanation:
To figure this out, just create some example points.
At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.
If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph
Answer:
10x + 5y = 11
Step-by-step explanation:
I usually find it in slope intercept then convert, it's easier for me.
First you find slope using delta y over delta x giving you -2/5.
so you have y=-2/5x + b
To find b plug in a point and solve down
1 = -2/5(3) +b
1+6/5 = b
b = 11/5
y=-2/5x + 11/5
Then you convert it to Ax+by=C form,
multiply by 5
5y = -10x + 11
move x
10x +5y = 11
I don't know the real answer, but I think it is C. (I am sorry if I am wrong).
Answer:
yes
Step-by-step explanation: