Ask question

Ask question

All categories

3 years ago

8

What if the yogurt shop has 8 gallons of milk ? How many milkshake can be made from 8 gallons with 1 pint of milk in each shake

?

2 answers:

nasty-shy [4]3 years ago

4 0

There are 8 pints in a gallon. So, 8*8=64 milkshakes

Vsevolod [243]3 years ago

3 0

Idk bit if u know it's right

You might be interested in

"Express as a mixed numeral: 39/8" is a problem found in a fifth-grade arithmetic textbook. This problem is BEST solved through:

Scilla [17]

Answer:

c. an algorithm

Step-by-step explanation:

Most math problems are best solved using an algorithm. Certainly, converting numbers from one form to another is easily done that way.

_____

The integer part is the whole-number quotient of the division. The fractional part is the remainder divided by the denominator:

39/8 = 32/8 + 7/8 = 4 7/8

5 0

2 years ago

What are the values of x and y in the equation

vaieri [72.5K]

Answer:

The correct choice is D

Step-by-step explanation:

Value of X=20 and then to know the value of y we need to add

52+52= 104

360-104= 256

256÷2= 128

Y=128

5 0

2 years ago

What is six plus six plus six

Likurg_2 [28]

6+6=12 + 6= 18
6x3=18
(I feel like u know the answer, just asking to give away free points. Either way the answer is 18 and thank you.)

5 0

3 years ago

Read 2 more answers

An investigator wishes to estimate the proportion of students at a certain university who have violated the honor code. having o

lesya692 [45]

<span>Asking a student if they have violated the honor code is not the proper question to ask, for a couple of reasons. First is that maybe they don't even know what the honor code is, and second maybe the students aren't being honest in fear of the reprecussions.</span>

3 0

3 years ago

A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage

fiasKO [112]

We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

$\begin{gathered} N=4+10+17+6+2 \\ N=39 \end{gathered}$

We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

$RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}$

This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

For grade B:

$RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}$

For grade C:

$RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}$

For grade D:

$RF_D=\frac{6}{39}\approx0.1538\approx15.38\text{ \%}$

For grade F:

$RF_D=\frac{2}{39}\approx0.0513\approx5.13\text{ \%}$

4 0

10 months ago