To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer: Wouldnt the height be 585? Rounded would be 590?
Step-by-step explanation:
I thought you would have to multiply 65 x 9.
Answer:
81 square metres is right anser follow me plse
Answer:

Step-by-step explanation:
Given

Required
Find the equivalent
We start by changing the / to *


Factorize 10a - 5

Expand 4a² - 1


Express (2a)² - 1² as a difference of two squares
Difference of two squares is such that: 
The expression becomes

Combine both fractions to form a single fraction

Divide the numerator and denominator by 2a - 1

Simplify the numerator


Hence,
= 