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4 years ago

12. The sum of two consecutive integers is no more than 57. what is the first possible integer?*

Mathematics

2 answers:

Umnica [9.8K]4 years ago

7 0

28+29=56 the first possible integer is 28

soldier1979 [14.2K]4 years ago

3 0

You can choose any two integers.
Like 1 and 2

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Help plz:)))I’ll mark u Brainliest

Vedmedyk [2.9K]

Answer:

ST = 8 m

Step-by-step explanation:

Since ∆PQR is congruent to ∆STU, therefore, the three sides of ∆PQR would be congruent or equal to the corresponding three sides of ∆STU.

PQ corresponds to ST.

Therefore, PQ is congruent to corresponding side ST, which is 8 m

ST = 8 m

5 0

3 years ago

You are running an experiment in class where you draw colored marbles out of a bag. There are

MaRussiya [10]

Answer:

32768 ways

Step-by-step explanation:

Given

Marbles = 8 marbles

Selection = 5 (with replacement)

Required

Determine the number of ways

Because it is a selection with replacement; each selection is as follows:

$First = 8\ marbles$

$Second = 8\ marbles$

$Third= 8\ marbles$

$Fourth = 8\ marbles$

$Fifth = 8\ marbles$

Total number of ways is then calculated as:

$Total = 8 * 8 * 8 * 8 * 8$

$Total = 32768$

5 0

3 years ago

How do I solve (2÷7)x = 300

igomit [66]

$\frac{2}{7}x=300$
$x=300( \frac{7}{2} )$
$x=1050$

8 0

3 years ago

Identify the product and express it in scientific notation. 4.7 x (6.02 x 10^23)

Anna11 [10]

Answer:

$\large\boxed{4.7\times(6.02\times10^{23})=2.8294\times10^{24}}$

Step-by-step explanation:

The scientific notation:

$a\times10^k\ \text{where}\ 1\leq a$

We have:

$4.7\times(6.02\times10^{23})=(4.7\times6.02)\times10^{23}=28.294\times10^{23}\\\\=2.8294\times10\times10^{23}=2.8294\times10^{24}$

6 0

3 years ago

If m 4 = (3x + 7) , and m 5 = (9x 43) , find m UPS.

IRISSAK [1]

Can you be more specific pls

8 0

3 years ago