The ratio of the measures of two complementary angles is 1:5. What are the measures of the angles? A. 30
Answer:
The circumference of the circle = 26π unit.
Step-by-step explanation:
Given:
Radius of the circle, r = "x+6"
Diameter of the circle, d = "3(x)+5"
We have to find the circumference of the circle in terms of pi.
Formula to be used:
Circumference of a circle = 2πr or πd
As we know that:
Radius = Half of diameter
So,
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
...<em>Arranging variables and constants. </em>
⇒ 
Plugging x = 7 we will find the radius and the diameter.
⇒ Radius = "x+6" = "7+6" = 13
⇒ Diameter = "3(x)+5" = 3(7)+5 =26
Lets find the circumference of the circle.
⇒ Circumference = 
Or
⇒ Circumference = 
The circumference of the circle = 26π unit.
Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
Answer:
c = 12.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Identify</u>
Leg <em>a</em> = 7.5
Leg <em>b</em> = 10
Hypotenuse <em>c</em> = <em>c</em>
<em />
<u>Step 2: Solve for </u><em><u>c</u></em>
- Substitute in variables [Pythagorean Theorem]: 7.5² + 10² = c²
- Rewrite: c² = 7.5² + 10²
- Evaluate exponents: c² = 56.25 + 100
- Add: c² = 156.25
- [Equality Property] Square root both sides: c = 12.5
Check the picture below.
bearing in mind that the slope goes by different names
average rate of change
rise over run
rate of change
but is basically the same cat in disguise with different costumes.
