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AlladinOne [14]
3 years ago
5

Let h = 3. What is the value of (27 ÷ h) · 5?

Mathematics
2 answers:
lys-0071 [83]3 years ago
7 0
27 ÷ 3 = 9
9 • 5 = 45
swat323 years ago
6 0
The answer would be 45 because 27/3=9 and 9*5=45
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Which expression is the same as 5 divided by 3
Rashid [163]
An expression that is equal to that question is 5/3 as a fraction or the solution times 3.
5 0
3 years ago
Read 2 more answers
How do you do x ^4-4? What is the x values?
VladimirAG [237]
We know that
A difference of two perfect squares (A² - B²)  <span>can be factored into </span><span> (A+B) • (A-B)
</span> then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2

the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2

i <span> is called the </span><span>imaginary unit. </span><span>It satisfies </span><span>  i</span>²<span>  =-1
</span><span>Both </span><span>  i </span><span>  and </span><span>  -i </span><span>  are the square roots of </span><span>  -1 
</span><span>√<span> -2 </span></span> =√<span> -1• 2  </span><span> = </span>√ -1 •√<span>  2  </span> =i • <span> √<span> 2 </span></span>
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3=  0 + √2<span> <span>i  
</span></span>x4=  0  - √2<span> i </span>

the answer is 

the values of x are
x1=+√2
x2=-√2
x3=  0 + √2 i  
x4=  0  - √2 i

3 0
3 years ago
PLEASE HELP ME!!! needing help now!
Phoenix [80]
The answer is it should be behind the 7  because you only moved one time in 1.7
7 0
3 years ago
What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

3 0
3 years ago
(27x4 - 18x3 + 9x 2) = 3x<br> Answer ASAP
shepuryov [24]

Answer:

x = 24

Step-by-step explanation:

27 x 4 = 108

18 x 3 = 54

9 x 2 = 18

108 - 54 + 18 = 3x

72 = 3x

72/3 = x

24 = x

7 0
3 years ago
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