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riadik2000 [5.3K]
3 years ago
12

The chi-square value for a one-tailed (lower tail) test when the level of significance is .1 and the sample size is 15 is a. 23.

685. b. 6.571. c. 7.790. d. 21.064.
Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

The degrees of freedom are given by:

df =n-1= 15-1=14

And if we look in the chi square distribution with 14 degrees of freedom and if we find a quantile who accumulates 0.1 of the area in the left we got:

\chi^2 = 7.790

And then the best answer would be:

c. 7.790

Step-by-step explanation:

For this case we know that we are using a one tailed (lower tail) critical value using a significance level of \alpha=0.1 and for this case we know that the ample size is n=15. The degrees of freedom are given by:

df =n-1= 15-1=14

And if we look in the chi square distribution with 14 degrees of freedom and if we find a quantile who accumulates 0.1 of the area in the left we got:

\chi^2 = 7.790

And then the best answer would be:

c. 7.790

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