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AlekseyPX
3 years ago
6

Can you please help?

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
4 0

Answer:

6.5 km per minute

Step-by-step explanation:

To calculate the average speed, you add the speed of one trip to the speed of the other then divide by 2.

The first trip was a speed of 80km/10 minutes or 8km per 1 minute.

The second trip was a speed of 100km/20 minutes or 5km per 1 minute.

To find the average, add and divide by 2:

\frac{8+5}{2}=\frac{13}{2}=6.5  km per minute  

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The diameter of a semicircle is 6 miles. What is the semicircle's perimeter?
koban [17]

Answer:

15.42mi

Step-by-step explanation:

Use the formula for a semicircle's perimeter.

P=\frac{1}{2}\pi *d+d

Plug in 6 for d.

P=\frac{1}{2}\pi*6+6

Let's use 3.14 for \pi, just to make it easier, but of course, if it states to round it to something else, just plug in that many values for \pi.

P=\frac{1}{2}(3.14)*6+6 \\ \\ P=1.57*6+6 \\ \\ P=9.42+6 \\ \\ P=15.42

5 0
3 years ago
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45% of the 647 students at Royal Oak High attended the football game. How many students did not attend?
Lostsunrise [7]
First multiply
.45*647= 291.15
291.15 is the number of people that attended 
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A d + b = 180
serg [7]
I know B is true, but i’m unsure for the other choices.
7 0
3 years ago
suppose Richard walks one kilometer every 10 minutes how many meters are there can you walk in an hour at this new rate
Ipatiy [6.2K]
One kilometer is 1000 meters.  One hour is 60 minutes, or six segments of 10 minutes each.  If you can walk 1000 meters in 10 minutes, you can walk 6000 in an hour (that is REALLY fast, by the way)
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3 years ago
(4 pts) If a rock is thrown vertically upward from the surface of Mars with an initial velocity of 15m/sec
Yuliya22 [10]

Answer:

Step-by-step explanation:

I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.

The position equation is

s(t)=-1.86t^2+15t  That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.

The first derivative of position is velocity:

v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):

0 = -3.72t + 15 and solve for t:\

-15 = -3.72t so

t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:

s(4.03) = -1.86(4.03)² + 15(4.03) so

s(4.03) = 30.2 meters.

Calculus is amazing. Much easier than most methods to solve problems like this.

7 0
2 years ago
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