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4 years ago

A jet flies at an altitude of 52,800 feet. What is the height of thejet in miles?

2 answers:

8 0

The height of the jet in miles is 10 miles. There are 5280 feet in a mile, so you would divide 52800 by 5280 and get 10 miles.

scZoUnD [109]4 years ago

5 0

10 miles is your answer because
1mile is 5280 feet
1:5280=x:52800
5280x=52800
x=52800/5280
x=10

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Im confused is 3a the same as 5a squared or 4b to 4b squared

NeX [460]

Step-by-step explanation:

In order to be like terms, the variables and exponents must be the same.

3a can be combined with 14a and 4a.

4b can be combined with 3b and 16b.

a² cannot be combined with any of the terms.

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3 years ago

I need help with this problem and would really appreiciate a short explanation too.<br> 15 PTS

inysia [295]

okay. the point has an x and y value. place them into the equation.

1=m(1)+b

m=slope, and theequation tells you that slope is 7.

1=7(1)+b

now you need to figure out what b is.

1=7(1)+b

1= 7 +b

-7 -7

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-6=B

b is 6. now place it into the equation, replacing the x and y values back.

y=7x-6.

write 7 and 6 in the boxes (the negative for the six has already been provided)

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3 years ago

Use the following problem to answer the question below:

Rom4ik [11]

Answer:

m∠ABD = m∠CBE ⇒ by subtracting a common angle from the given angles

Step-by-step explanation:

∵ m∠ABE = m∠CBD

∵ m∠ABD = m∠ABD + m∠DBE

∵ m∠CBD = m∠CBE + m∠EBD

∵ ∠EBD is common angle between them

∴ m∠ABD = m∠CBE

6 0

3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

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vagabundo [1.1K]

Answer:

Step-by-step explanation:

$\cos ~A=0.5=cos~60 \\A=60^\circ\\B=180-A=180-60=120\\\angle~B=120^\circ$

3 0

3 years ago