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artcher [175]
3 years ago
11

sue can hit a golf ball 26.4 yards Johnny can hit a ball 10 times as further as sue. how many can John hit the ball????

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0
264 yards, all you need to do when you are multiplying decimals by powers of ten (10, 100, 1000, etc.) is move the decimal point to the right depending on how many zeros there are.
Marina CMI [18]3 years ago
7 0
John can hit the ball 264 yards
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Geometry math question no Guessing and Please show work thank you
zimovet [89]

Perpendicular bisectors of the sides of triangles are used to draw the circle that passes through corners of the triangle.

Gien that perpendicular bisectors of a triangle are concurrent.

So that means common point will be A) Circumcenter.

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4 years ago
Write 5 next terms:1;2;4;7;11;16​
Alex_Xolod [135]

Answer:

22,29,37,46,56

adding 1, then 2 then 3 and so on

4 0
3 years ago
Felix earns $450 per week plus 3% of sales over $4800. Felix’s sales are $53000. How much does Felix earn?
Leni [432]

1.  Felix’s sales are $53000. He has 3% of sales over $4800, then he has 3% of sales $(53000-4800)=$48200.

Now

$48200 -- 100%

$x -- 3%.

Write a proportion:

\dfrac{48200}{x}=\dfrac{100}{3},\\ \\x=\dfrac{48200\cdot 3}{100}=482\cdot 3=1446.

Thus, he additionally gets $1446.

2. If he earns $450 per week and earns $1446 of sales, then Felix earns

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5 0
3 years ago
Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to o
Roman55 [17]

Answer:

Range = 11-2=9

\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5

\sigma^2 =8.25 \approx 8.3

\sigma = \sqrt{8.25}= 2.87 \approx 2.9

Step-by-step explanation:

Assuming this question: "Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. 2,3,4,5,6,7,8,9,10,11 "

Solution to the problem

The range is defined as Range = Max -Min and if we replace we got:

Range = 11-2=9

Now we can calculate the population mean with this formula:

\mu =\frac{\sum_{i=1}^n X_i}{N}

And if we replace we got:

\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5

The population variance is given by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And after replace we got: \sigma^2 =8.25 \approx 8.3

And the population standard deviation would be just the square root of the variance and we got:

\sigma = \sqrt{8.25}= 2.87 \approx 2.9

4 0
4 years ago
What is the answer to 7,8 I know I circle something but I guessed
guapka [62]
1 is a thanks for letting me help
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4 years ago
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