Answer:
We have the magnitude, M, and the angle A.
(The angle is always measured from the +x-axis)
Then we have that:
x = M*cos(A)
y = M*sin(A)
in this case:
M = 9m
A = -80°
x = 9m*cos(-80°) = 1.562
y = 9m*sin(-80) = -8.86m
Now, the component parallel to the x axis is:
x = 9m*cos(-80°) = 1.562 m
And the slope of something parallel to the x-axis is always zero, as this is a constant line.
Given:
Diameter of outer circle = 20 inches.
We need to find the Area of the outer circle to get the radius of the inner circle.
Area = πr²
Outer circle Area = 3.14 * (10in)² = 314 in²
314 in² * 64% probability = 200.96 in² Area of the inner circle.
200.96 in² = 3.14 * r²
200.96 in² / 3.14 = r²
64 in² = r²
√64 in² = √r²
8 in = r
radius of inner circle is 8 inches.
.25p + 5 = .50p + 2
-.25p = -3
-p = -12
p= 12 problems
Y = -5x + 12 since the slope of that line is -5x and in order to pass through that point the y intercept must be 12
