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pogonyaev
3 years ago
5

In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many

lone pairs of electrons are present in the Lewis structure of calcium sulfide? one two three four none

Chemistry
2 answers:
allochka39001 [22]3 years ago
8 0
Their are 4 valence electrons left, which means there is 2 lone pairs. I think.

Vedmedyk [2.9K]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

Chemical formula of calcium sulfide is CaS. Since there are two valence electrons in calcium and six valence electrons in sulfur.

So, in order to attain stability, calcium will donate its two extra electrons to the sulfur atom. Therefore, calcium sulfide is an ionic compound.

Thus, we can conclude that there will be only two lone pair of electrons in a calcium sulfide molecule.

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Fittoniya [83]

Answer:

10^-3 M.

Explanation:

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Molar mass of 1084.24 g mol^−1. The chemical compound that is ADH is very important in human body as it helps in regulation of blood and also the regulation of water in human body.

STEP ONE: Convert the value of mg/ml to g/l. That is;

35mg/ml = 35g/l.

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The number of moles = 35 /35000 = 10^-3 moles.

STEP THREE: Determine the concentration.

Number of moles = concentration × volume.

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2 years ago
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AveGali [126]
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3 years ago
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