In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many
lone pairs of electrons are present in the Lewis structure of calcium sulfide? one two three four none
2 answers:
Answer: Option (b) is the correct answer.
Explanation:
Chemical formula of calcium sulfide is CaS. Since there are two valence electrons in calcium and six valence electrons in sulfur.
So, in order to attain stability, calcium will donate its two extra electrons to the sulfur atom. Therefore, calcium sulfide is an ionic compound.
Thus, we can conclude that there will be only two lone pair of electrons in a calcium sulfide molecule.
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Answer: Equilibrium concentration of at
is 4.538 M
Explanation:
Initial concentration of = 0.056 M
Initial concentration of = 4.60 M
The given balanced equilibrium reaction is,
Initial conc. 0.056 M 4.60 M 0 M 0 M
At eqm. conc. (0.056-x) M (4.60-2x) M (x) M (6x) M
The expression for equilibrium constant for this reaction will be,
Given : equilibrium concentration of =x = 0.031 M
Concentration of = (4.60-2x) M =
=4.538 M
Thus equilibrium concentration of at
is 4.538 M