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pogonyaev
3 years ago
5

In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many

lone pairs of electrons are present in the Lewis structure of calcium sulfide? one two three four none

Chemistry
2 answers:
allochka39001 [22]3 years ago
8 0
Their are 4 valence electrons left, which means there is 2 lone pairs. I think.

Vedmedyk [2.9K]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

Chemical formula of calcium sulfide is CaS. Since there are two valence electrons in calcium and six valence electrons in sulfur.

So, in order to attain stability, calcium will donate its two extra electrons to the sulfur atom. Therefore, calcium sulfide is an ionic compound.

Thus, we can conclude that there will be only two lone pair of electrons in a calcium sulfide molecule.

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given the mass lost during the reaction when the alka seltzer is the limiting reagent and that the molar mass of carbon dioxide
Vadim26 [7]
Alka-seltzer is an effervescent antacid which neutralizes the acid of the stomach by generating CO2. The chemical formula of alka-seltzer is C16H17NaO14. In this case, if we are given the mass of the antacid used, then by stoichiometry, mass alka-seltzer * (1/ molar mass of alk-selz) * (1 mol Co2 / 1 mol alk-seltz) * (44 g/molCo2). That is how you get the mass of Co2 produced.
5 0
3 years ago
You're provided with a bottle labled [CoCl2.6H2O] = 0.056 M in 4.60 M HCl. You heat a small volume of the solution in a hot wate
sweet [91]

Answer: Equilibrium concentration of [Cl^-] at 50^0C is 4.538 M

Explanation:

Initial concentration of CoCl_2 = 0.056 M

Initial concentration of Cl^- = 4.60 M

The given balanced equilibrium reaction is,

               COCl_2+2Cl^-\rightleftharpoons [CoCl_4]^{2-}+6H_2O

Initial conc.          0.056 M      4.60 M        0 M       0 M

At eqm. conc.     (0.056-x) M   (4.60-2x) M   (x) M    (6x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CoCl_4]^{2-}\times [H_2O]^6}{[CoCl_2]^2\times [Cl^-]^2}

Given : equilibrium concentration of [CoCl_4]^{2-} =x =  0.031 M

Concentration of Cl^- = (4.60-2x) M  = (4.60-2\times 0.031) =4.538 M  

Thus equilibrium concentration of [Cl^-] at 50^0C is 4.538 M

8 0
3 years ago
Using the balanced equation below,
Zielflug [23.3K]

Answer:

Mass = 6.538 g

Explanation:

Given data:

Mass of zinc hydroxide produced = 9.65 g

Mass of zinc required = ?

Solution:

Chemical equation:

Zn + 2MnO₂ + H₂O      →      Zn(OH)₂ + Mn₂O₃

Number of moles of zinc hydroxide:

Number of moles = mass/molar mass

Number of moles = 9.65 g/ 99.42 g/mol

Number of moles = 0.1 mol

now we will compare the moles of zinc and zinc hydroxide,

                  Zn(OH)₂           :          Zn

                       1                  :          1

                    0.1                  :         0.1

Mass of zinc required:

Mass = number of moles × molar mass

Mass = 0.1 mol × 65.38 g/mol

Mass = 6.538 g

8 0
3 years ago
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schepotkina [342]
Yes because she is holding the weight of the box.
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Which of the following is not a type of fault?
bekas [8.4K]

normal is the answer


8 0
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