Basic facts about sex and reproduction, as told to a child
Answer:
Number of moles of solute = 0.6 mole
Mass =13.8 g
Explanation:
Given data:
Number of moles of sodium = ?
Volume = 2.0 L
Molarity = 0.30 M
Mass in gram of sodium= ?
Solution:
<em>Number of moles:</em>
Molarity = number of moles of solute / volume in litter
Number of moles of solute = Molarity × volume in litter
Number of moles of solute = 0.30 M × 2.0 L
Number of moles of solute = 0.6 mole
<em>Mass in gram:</em>
Mass = Number of moles × molar mass
Mass = 0.6 mole× 23 g/mol
Mass =13.8 g
The student was not successful.
Consider the standard reduction potentials.
Li⁺ + e⁻ ⇌ Li; E° = -3.04 V
2H₂O + 2e⁻ ⇌ H₂ + 2OH⁻; E° = -0.83 V
To reduce Li⁺ to Li, the student must apply 3.04 V.
However, it takes only 0.83 V to reduce water to hydrogen.
Thus, the student will get H₂ instead of Li.
Answer:
The correct answer is a hypothesis.
Period : the no. of electron shells
group: the last no. of electron configuration
