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3 years ago

Why can't liquids change volume but gases can

Chemistry

1 answer:

brilliants [131]3 years ago

8 0

The Particles in the gas are to far apart from each other, so they do not have a volume nor shape.

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Calculate the molality of a solution prepared by dissolving 25.0 g of sodium chloride (NaCl) in 625 g of water

umka2103 [35]

Answer: m= 0.69 m or mol/kg

Explanation: Molality is expressed as moles per unit kilograms of solvent or m= n / kg

First convert 25.0 g NaCl to moles

25.0 g NaCl x 1 mole NaCl / 58 g NaCl

= 0.43 moles NaCl

Next convert 625 g H2O to kilograms

625 g H2O x 1 kg / 1000 g H2O

= 0.625 kg H2O

Substitute the values in the formula

m = n / kg

= 0.43 mole NaCl / 0.625 kg

= 0.69 m or mole / kg

6 0

3 years ago

Which statement from Dalton's atomic theory was incorrect?

balandron [24]

Use more detail please.

4 0

3 years ago

How does an ecosystem benefit when leaves fall from a tree and decompose on the soil?

nexus9112 [7]

Answer:

A. Nutrients are released into the soil

5 0

3 years ago

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What part of an atom bonds with other atoms

mote1985 [20]

Atoms that share electrons in a chemical bond have covalent bonds. An oxygen molecule (O2) is a good example of a molecule with a covalent bond. Ionic bonds occur when electrons are donated from one atom to another.

7 0

4 years ago

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Calcium carbonate forms limestone, one of the most common rocks on Earth. It also forms stalactites, stalagmites, and many other

max2010maxim [7]

Answer: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$ , 0.533 L

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

According to avogadro's law, 1 mole of every substance occupies 22.4 L of volume at STP.

Number of moles = $\frac{\text {given mass}}{\text {Molar mass}}$

moles of calcium carbonate = $\frac{2.38g}{100g/mol}=0.0238mol$

As 1 mole of calcium carbonate produces = 22.4 L of carbon dioxide at STP

Thus 0.0238 moles of calcium carbonate produces = $\frac{22.4 L}{1}\times 0.0238=0.533L$ of carbon dioxide at STP

3 0

3 years ago