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serious [3.7K]
3 years ago
6

Which compound is an Arrhenius base?(1) CH3OH (3) LiOH (2) CO2 (4) NO2

Chemistry
2 answers:
nydimaria [60]3 years ago
7 0
Lithium Hydroxide (LiOH) is an Arrhenius base
gregori [183]3 years ago
5 0
♥ (LiOH)
♥ (Lithium Hydroxide) 
Is a Arrhenius base. <span />
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6. If the broken wire of the top branch
vagabundo [1.1K]

Answer: When two light bulbs are connected in parallel, which is true? A. The total resistance is less than the resistance of either bulb alone. B. The Voltage provided

Explanation:

3 0
2 years ago
10. Make your own unique problem for your classmates to solve for the
babymother [125]

Answer:

Explanation:

<u>Problem</u>:

In a gender based experiment, the blood pressure of different ages of men is been checked and recorded to determine if there is any correlation. What will be the independent, dependent and controlled variables?

<u>Answer</u>:

A controlled variable is the variable that is left constant throughout the course of an experiment. The controlled variable here is the gender.

A dependent variable is the variable that is been determined or measured during the course of an experiment. The dependent variable here is the blood pressure.

An independent variable is the variable that is intentionally or decidedly altered during the course of an experiment. The independent variable here is the age.

3 0
3 years ago
A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in 0.245 kilograms of water. If the molal freezing point consta
aalyn [17]

Answer:

- 0.99 °C ≅ - 1.0 °C.

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

m is the molality of the solution (m = moles of solute / kg of solvent = (23.5 g / 180.156 g/mol)/(0.245 kg) = 0.53 m.

<em>∴ ΔTf = (Kf)(m)</em> = (-1.86 °C/m)(0.53 m) =<em> - 0.99 °C ≅ - 1.0 °C.</em>

4 0
4 years ago
How many significant figures in 8400
IrinaK [193]

Answer:

there are two significant figures is the number 8400

Explanation:

5 0
3 years ago
Read 2 more answers
A monatomic ideal gas that is initially at 1.50 * 105 Pa and has a volume of 0.0800 m3 is compressed adiabatically to a volume o
lubasha [3.4K]

Answer:

300000Pa or 3×10^5 Pa

Explanation:

Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.

Using Boyle's law

P1V1 = P2V2

P1 is the initial pressure = 1.5×10^5Pa

V1 is the initial volume = 0.08m3

P2 is the final pressure (required)

V2 is the final volume = 0.04 m3

From the formula, P2 = P1V1/V2

P2 = 1.5×10^5 × 0.08 ÷ 0.04

= 300000Pa or 3×10^5 Pa.

8 0
3 years ago
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