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serious [3.7K]
3 years ago
6

Which compound is an Arrhenius base?(1) CH3OH (3) LiOH (2) CO2 (4) NO2

Chemistry
2 answers:
nydimaria [60]3 years ago
7 0
Lithium Hydroxide (LiOH) is an Arrhenius base
gregori [183]3 years ago
5 0
♥ (LiOH)
♥ (Lithium Hydroxide) 
Is a Arrhenius base. <span />
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A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
Elan Coil [88]

Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)  ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol

6 0
3 years ago
If 0.500 mol of each of the following solutes is dissolved in 2.0 L of water, which will cause the greatest increase in the boil
serious [3.7K]

Answer is: D. Na2SO4.

b(solution) = 0.500 mol ÷ 2.0 L.

b(solution) = 0.250 mol/L.

b(solution) = 0.250 m; molality of the solutions.

ΔT = Kf · b(solution) · i.

Kf - the freezing point depression constant.

i - Van 't Hoff factor.

Dissociation of sodium sulfate in water: Na₂SO₄(aq) → 2Na⁺(aq) + SO₄²⁻(aq).

Sodium sulfate dissociates on sodium cations and sulfate anion, sodium sulfate has approximately i = 3.

Sodium chloride (NaCl) and potassium iodide (KI) have Van 't Hoff factor approximately i = 2.

Carbon dioxide (CO₂) has covalent bonds (i = 1, do not dissociate on ions).

Because molality and the freezing point depression constant are constant, greatest freezing point lowering is solution with highest Van 't Hoff factor.

8 0
3 years ago
Read 2 more answers
Which sub-layer thins out into space, where there is no air
KengaRu [80]
<span>The "exosphere" is the most distant and tenuous "layer" of our atmosphere.</span>
3 0
2 years ago
Read 2 more answers
Answer True or False for each of the following statements. (a) The carburization surface was maintained at slightly less than 0.
fomenos

Answer:

verdadero/a

falso/b

verdadero/c

Explanation:

6 0
2 years ago
What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?
SpyIntel [72]
When the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2

2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) *                                           (1L ca(OH)2/0.585 mol Ca(OH)2 

                                          = 20.4 L
8 0
3 years ago
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