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defon
3 years ago
11

Why does liquid exerts pressure​

Chemistry
1 answer:
andriy [413]3 years ago
3 0

Answer:

The particles of fluids are constantly moving in all directions at random. As the particles move, they keep bumping into each other and into anything else in their path. These collisions cause pressure, and the pressure is exerted equally in all directions.

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(GIVING BRAINLIEST) do what the following image says.
S_A_V [24]

Answer:

hope it helps.

<h3>stay safe healthy and happy.<u>.</u><u>.</u></h3>

7 0
3 years ago
Read 2 more answers
iron has a density of 7.86 g cm3 could a block of metal with a mass of 18.2 and a volume of 2.56 cm^3 be iron?
satela [25.4K]

The density of the block will be "7.11 gm/cm³". A further explanation is provided below.

Given values are:

Density of iron,

  • 7.86 \ g/cm^3

Mass of block of metal,

  • 18.2 \ gm

Volume of block,

  • 2.56 \ cm^3

By using the formula,

→ Density = \frac{Mass}{Volume}

then,

→ The density of block will be:

= \frac{Mass}{Volume}

= \frac{18.2}{2.56}

= 7.11 \ gm/cm^3

Learn more:

brainly.com/question/10804879

7 0
3 years ago
Suppose oxygen was much less electronegative than it is, so that hydrogen-oxygen bonds were much less polar and hydrogen bonds c
spayn [35]
Water would have a much lower boiling point much like its other hydrides and it would loss its ability to dissolve polar substances plus it couldn't form water columns so no more cohesion between water molecules
6 0
3 years ago
Read 2 more answers
How many moles are in 1.5L of 0.40M Na2SO4?​
anzhelika [568]

Answer:

0.60 moles of Na₂SO₄

Explanation:

Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.

A solution of Na₂SO₄ 0.40M contains 0.40 moles of solute (Na₂SO₄) per liter of solution.

As you have 1.5L of solution, moles of Na₂SO₄:

1.5L × (0.40mol / L) = <em>0.60 moles of Na₂SO₄</em>

7 0
3 years ago
A sample of rubidium contains two different isotopes. 72.15% of the sample
Leona [35]

Answer:

Average atomic mass  = 85.557 amu.

Explanation:

Given data:

Percent abundance of Rb-85 = 72.15%

Percent abundance of Rb-87 = 27.85%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (72.15×85)+(27.85×87) /100

Average atomic mass =  6132.75 + 2422.95 / 100

Average atomic mass = 8555.7 / 100

Average atomic mass  = 85.557 amu.

4 0
3 years ago
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