Answer:
10.69% probability that all 12 flights were on time
Step-by-step explanation:
For each flight, there are only two possible outcomes. Either it was on time, or it was not. The probability of a flight being on time is independent of any other flight. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
83% of recent flights have arrived on time.
This means that 
A sample of 12 flights is studied.
This means that 
Calculate the probability that all 12 flights were on time
This is P(X = 12).


10.69% probability that all 12 flights were on time
First: 13 x 8 = 104
Second: 8/2 = 4
Third: 104 + 4 = 108
Your answer is 108
Answer:
-3m+2/3. 2/3 is a fraction
Step-by-step explanation:
The lower left corner is the answer.
Angle 1 is congruent to angle 5 because they are alternate interior angles (assuming AB || DE)
They are on the inside of the parallel train tracks. By "train tracks" I mean the horizontal lines AB and DE. So they are considered interior angles. They are on alternate sides of the transversal AE. Angle 1 is on the right side while angle 5 is on the left side. These two facts are why they are considered alternate interior angles.