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Elena-2011 [213]
3 years ago
11

Please help, thank you

Mathematics
1 answer:
solmaris [256]3 years ago
8 0

Answer:

1.

8x + 6y = 28

9x + 3y = 39

Set to equal y.

8x + 6y = 28

6y = -8x + 28

y = -8/6x + 28/6

y = -4/3x + 14/3

9x + 3y = 39

3y = -9x + 39

y = -9/3x + 39/3

y = -3x + 13

Set equal to each other.

-4/3x + 14/3 = -3x + 13

Combine like terms.

5/3x = 25/3

Multiply by 3/5

x = 5

Plug x in.

y = -3(5) + 13

y = -15 + 13

y = -2

(5, -2)

2.

-2x - 9y = -3

-7x - 9y= -33

Set equal to y.

-2x - 9y = -3

-9y = 2x - 3

y = -2/9x + 3/9

y = -2/9x + 1/3

-7x - 9y= -33

-9y = 7x - 33

y = -7/9x + 33/9

y = -7/9x + 11/3

Set equal to each other

-2/9x + 1/3 = -2/9x + 1/3

0 = 0

infinitely many solutions

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3 0
2 years ago
Type the correct answer in the box. Round your answer to the nearest integer.
umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}

\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}

sin(∠ADB) = \frac{30\text{sin}(120)}{35}

                 = 0.74231

m∠ADB = \text{sin}^{-1}(0.74231)

             = 47.92°

             ≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

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