Answer:
<u><em>Question 1:</em></u>
<em>The sum of interior angles of a polygon can be found by the following formula:</em>
(n-2) × 180
<em><u>Where n is the no. of sides</u></em>
A pentagon has 5 sides
So,
= (5-2) × 180
= (3) × 180
= 540 degrees
<u><em>Question 2:</em></u>
Since The sum of interior angles of a regular octagon is 1080 and the total interior angle are 8
So, Measure of interior angle = 
Measure of interior angle = 135 degrees
<u><em>Question 3:</em></u>
<em><u>Since, one interior angle in a hexagon measures 120 degrees.</u></em>
So,
<em>The interior angle should be subtracted by 180 to get the exterior angle.</em>
Exterior angle = 180-120
Exterior Angle = 60 degrees
Funny cause I just did something similar a few minutes ago
Answer:
3 would be your y intercept
then from the point 0,0 put 2 in as slope
Step-by-step explanation:
First turn the equation into y=mx+b (slope-intercept form)
Which turns into y= -2x+3
in y=mx+b
m is slope and b is y intercept
3 would be your y intercept
then from the point 0,0 put 2 in as slope
Hope this helps! have a nice day! Please consider making me Brainliest!
Answer:
A and B are correct
Step-by-step explanation:
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
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