16x+3y=251 and 8x+4y=148 then you set them up to each other and cancel one coefficient through elimination or find out what X or Y equals and substitute into either equation
The area of a circle is equal to the radius squared times pie, basically:

The radius is 3, so we multiply 3 times 3 times pie to get the area.
You're gonna want to plug in the following into a calculator:

After getting 28.26 from such calculator, you need to round to the tenths place. In this number, the tenths place is the 2 next to the decimal on the right. Because the number after the 2 is a 6, that means we need to simplify the answer to (28.3). When you are rounding a number, you look at the number to the right, if it is 5 or bigger, add one and remove the rest, if it is less than 5, just get rid of the rest and leave it as it is.
Answer:
104.7 in^3
Step-by-step explanation:
Step one:
given data
The ball has a radius of 5 inches and
the cylinder has a height of 8 inches
Step two:
The volume of the cylinder

substitute our data

The volume of the ball

substitute our data

The space will have a volume of
=628.4-523.7
=104.7 in^3
Let the leading term of the polynomial, f(x), be axⁿ.
Examine the possibilities.
n a x -> - ∞ x -> +∞
------- ---- ----------- ------------
even a>0 f -> +∞ f -> +∞ Not true
even a<0 f-> - ∞ f-> -∞ True
odd a>0 f-> -∞ f-> +∞ Not true
odd a<0 f-> +∞ f-> -∞ Not true
Answer:
(a) the degree of the polynomial is even, and
(b) the coefficient of the leading term is negative.
<u>Answer:
</u>
The point-slope form of the line that passes through (6,1) and is parallel to a line with a slope of -3 is 3x + y – 19 = 0
<u>Solution:
</u>
The point slope form of the line that passes through the points
and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line.
are the points that passes through the line.
From question, given that slope “m” = -3
Given that the line passes through the points (6,1).Hence we get 
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -3 can be found out.
y – 1 = -3(x – 6)
y – 1 = -3x +18
On rearranging the terms, we get
3x + y -1 – 18 = 0
3x + y – 19 = 0
Hence the point slope form of given line is 3x + y – 19 = 0