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3 years ago

A triangle has an exterior angle with a measure of 120°. Can you determine the measures of the interior angles? Explain.

1 answer:

3 0

If the exterior angle is 120 degrees, you subtract 120 degrees from 360 degrees (the two angles form a circle) and get 240 degrees.
This is not a possible angle for a triangle because the angles in a triangle always add up to 180 degrees. Also, angles in triangles can’t be more than 180 degrees

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3 years ago

How do I prove this problem?

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3 years ago

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

3 years ago

X= 2 and y = 4, then -X-XY

Fed [463]

Answer:

-10

Step-by-step explanation:

= -X - XY

= -2 - 2×4

= -2 - 8

= -10

therefore, -X - XY = -10

5 0

2 years ago

Read 2 more answers

John wants to fence in a portion of his backyard. ... How many feet of fencing does john need to buy to enclose this area? ... H

Lelechka [254]

For this problem you need to find the area.
To find area, you multiply the width by the length.
You multiply 12 1/2 by 5 1/2 and you get 31 1/4
This is how you do it::

= 25/2 × 5/2

= (25 × 5) / (2 × 2)

= 125/4

= 125/4

= 31 1/4

So you know that the area is 31 1/4 yards.
In the question it asks HOW MANY FEET so we have to convert 31 1/4 yards to feet.
1 yard= 3 feet
31 1/4 *3= 93.75
John need to buy 93.75 feet of fencing to enclose the area.

3 0

3 years ago