The complete question is
"Find the general solution of the given differential equation
y''-y=0, y1(t)=e^t , y2(t)=cosht
The function
is the solution of the given differential equation.
The function y(t)=cosht is the solution of given differential equation.
<h3>What is a function?</h3>
The function is a type of relation, or rule, that maps one input to specific single output.
Given;

Given differential equations are,
y''-y = 0
So that,
Substitute values in the given differential equation.

Therefore, the function
is the solution of the given differential equation.
Another function;
So that,

Hence, function y(t)=cosht is solution of given differential equation.
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The solutions would be 3 and 9
Answer:
Solve for
K
by simplifying both sides of the equation, then isolati.ng the variable.
K
=
m
v
2 i.f yo.u wa.nt th.e re.al answ.er g.o h.ere: >>>>https://www.math.way.com/po.pular-prob.lems/Alg.ebra/229798
2
Step-by-step explanation:
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Given information
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Area = 3x² + 14x + 8
Length = x + 4
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Formula
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Area = Length x Width
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Find Width
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3x² + 14x + 8 = (x + 4) x width
width = (3x² + 14x + 8) ÷ (x + 4)
width = (x+4)(3x+2) ÷ (x + 4)
width = 3x + 2
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Answer: The width is 3x + 2 (Answer C)
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Answer:
-8a^2 + 9a
or
9a - 8a^2
the answer is c
Step-by-step explanation: