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chubhunter [2.5K]
2 years ago
13

1. Find the LCM of 35,14 using prime factorization.

Mathematics
1 answer:
vekshin12 years ago
3 0

Answer:

Step-by-step explanation:

1) 35 = 5 * 7

  14 = 2 * 7

LCM = 2 * 5 * 7 = 70

2)  15 = 3 * 5

    12 = 2 * 2 * 3

LCM = 2* 2 * 3 * 5 = 60

3) 5 = 5

    9 = 3 * 3

  15 = 3 * 5

LCM = 3*3 * 5 = 45

4)8 = 2 * 2 * 2 = 2³

  10 = 2 *5

   12 = 2 * 2 *3 = 2² * 3

LCM = 2³ * 3 * 5 = 120

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Step-by-step explanation:

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3 years ago
Waves with an amplitude of 2 feet pass a dock every 30 seconds. Write an equation for a cosine function to model the height of a
kolbaska11 [484]

Answer:

The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)

Step-by-step explanation:

The cosine function equation is given as follows h = d + a·cos(b(x - c))

Where:

\left | a \right | = Amplitude

2·π/b = The period

c = The phase shift

d = The vertical shift

h = Height of the function

x = The time duration of motion of the wave, t

The given data are;

The amplitude \left | a \right | = 2 feet

Time for the wave to pass the dock

The number of times the wave passes a point in each cycle = 2 times

Therefore;

The time for each complete cycle = 2 × 30 seconds  = 60 seconds

The time for each complete cycle = Period = 2·π/b = 60

b = π/30 =

Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have

h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)

The cosine function is h = 2·cos((π/30)·t).

4 0
3 years ago
The surface area for a rectangular prism with a square base is SA=2s2+4sh.
torisob [31]
We know that
[surface area for a rectangular prism with a square base ]=2*s²+4*s*h

2*s²----> Is the surface area of the bases
4*s*h---> is the lateral area
s=2 units
h=4 units

[surface area for a rectangular prism with a square base ]=2*2²+4*2*4
surface area=8+32----> 40 units²

the answer is
40 units²
3 0
3 years ago
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kipiarov [429]
40x10 is the correct one
5 0
2 years ago
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The water level in a lake was 22 inches below normal at the beginning of March. The water level decreased by 3 1/6 inches in Mar
Vinvika [58]
At the beginning it was 22 inches below normal (-22).
Then it decreased by 3 1/6 (-19/6).
Then increased by 1 6/7 (+13/7)

-22 - 19/6 + 13/7
-924/42 - 133/42 + 78/42
-1057/42 + 78/42
-979/42
-23 13/42

It was 23 13/42 inches below normal after April.
8 0
3 years ago
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