1. Find the LCM of 35,14 using prime factorization.

Mathematics

1 answer:

vekshin13 years ago

3 0

Answer:

Step-by-step explanation:

1) 35 = 5 * 7

14 = 2 * 7

LCM = 2 * 5 * 7 = 70

2) 15 = 3 * 5

12 = 2 * 2 * 3

LCM = 2* 2 * 3 * 5 = 60

3) 5 = 5

9 = 3 * 3

15 = 3 * 5

LCM = 3*3 * 5 = 45

4)8 = 2 * 2 * 2 = 2³

10 = 2 *5

12 = 2 * 2 *3 = 2² * 3

LCM = 2³ * 3 * 5 = 120

You might be interested in

Three times the sum of three consecutive integers is 72. What are the integers?

eimsori [14]

The answer is: 23+ 24+ 25 = 72

6 0

3 years ago

Read 2 more answers

Write the equation of the line that passes through the points (4,9) and (9,1). Put

Sonbull [250]

Answer:

y=-8/5x+77/5

Step-by-step explanation:

The equation of line that passes through the points (4, 9) and (9, 1) is y=-8/5x+77/5. Hope it helps!

7 0

3 years ago

cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

5 0

3 years ago

Read 2 more answers

What is the missing reason in the proof

Gwar [14]

Answer:

SSS Congruence Theorem

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Cameron is building a model of the Eiffel Tower