Question:
1 answer:
A) The vertices of the ABCD square are:
(2,2), (1(4), (3,5), and (4,3).
The reflection over the x-axys keeps the same x-coordinate and changes the y-coordinate ot its negative.
So, the vertices of the square A'B'C'D' are:
(2,-2), (1,-4), (3,-5), and (4,-3).
You can see the figure attached showing the four vertices.
<span>B. Is AB congruent to A'B'? Explain
Answer:
Yes, they are congruent. You can affirm that because reflections are transformations that do not change either sizes or angles, but keep them, so the two squares are congruent.
C. Is the area of ABCD ≈ area of A'B'C'D'? Explain.
Answer:
Yes, the two areas are equal since you have shown that the two figures are congruent.
</span>
(2,2), (1(4), (3,5), and (4,3).
The reflection over the x-axys keeps the same x-coordinate and changes the y-coordinate ot its negative.
So, the vertices of the square A'B'C'D' are:
(2,-2), (1,-4), (3,-5), and (4,-3).
You can see the figure attached showing the four vertices.
<span>B. Is AB congruent to A'B'? Explain
Answer:
Yes, they are congruent. You can affirm that because reflections are transformations that do not change either sizes or angles, but keep them, so the two squares are congruent.
C. Is the area of ABCD ≈ area of A'B'C'D'? Explain.
Answer:
Yes, the two areas are equal since you have shown that the two figures are congruent.
</span>
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Given that the function is
We need to determine the average rate of change over the interval
<u>Value of f(x) when x = 0:</u>
Substituting x = 0 in the function , we have;
Thus, the value of f(0) is 7.
<u>Value of f(x) when x = 5:</u>
Substituting x = 5 in the function , we have;
Thus, the value of f(5) is 2.
<u>Average rate of change:</u>
The average rate of change can be determined using the formula,
where and
Thus, we have;
Thus, the average rate of change over the interval is -1.