The first step is to write this equation into general form. The
general form of an equation is:
ax^2 + bx + c = 0
To make this equation to general form, you have to simplify
the equation first.
2/3(x-4) (x+5) = 1
2/3 (x^2 + 5x – 4x – 20) = 1
2/3(x^2 + x -20) = 1
2/3x^2 + 2/3x – 40/3 = 1
2/3x^2 + 2/3x – 40/3 – 1 = 0
2/3x^2 +2/3x – 43/3 = 0
Therefore, a = 2/3 ; b = 2/3 ; c = -43/3
Answer:

Step-by-step explanation:
in the equation given these are the values:
a=1 b= -5 c= -7
if we plug this in the quadratic formula 
this is simplified to 
hope this helped
Step 
<u>Find the slope of the given line</u>
Let

slope mAB is equal to

Step 
<u>Find the slope of the line that is perpendicular to the given line</u>
Let
CD ------> the line that is perpendicular to the given line
we know that
If two lines are perpendicular, then the product of their slopes is equal to 
so

Step 
<u>Find the equation of the line with mCD and the point (3,0)</u>
we know that
the equation of the line in the form point-slope is equal to

Multiply by
both sides


therefore
the answer is
the equation of the line that is perpendicular to the given line is the equation 
Y =0.5x +2 The y-intercept is found by the coordinates (0,2) and the change is 0.5
Step-by-step explanation:
B. One of the graphs is positioned 4 units lower than the other.
(as the drawing attached)