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Elina [12.6K]
3 years ago
12

Can you help me list 5hese from least to greatest

Mathematics
1 answer:
g100num [7]3 years ago
4 0
Ok sweetheart, the easy way to solve these problems is to change them to all the same form for example "decimal" after that you sort them! just don't forget to remember which is which!!! so this is how you solve.

squared 25, 4.26, 3 1/5 2^3,2.58
i converted each so your answer is A.

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In an arithmetic​ sequence, the nth term an is given by the formula an=a1+(n−1)d​, where a1 is the first term and d is the commo
Dmitry_Shevchenko [17]

Answer:

a_{10} = \frac{10}{65536}

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

a_{3} - a_{2} = a_{2} - a_{1}

We have that:

a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}

a_{3} - a_{2} = a_{2} - a_{1}

\frac{5}{2} - 10 = 10 - 40

\frac{-15}{2} \neq -30

This is not an arithmetic sequence.

This sequence is geometric if:

\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}

\frac{\frac{5}[2}}{10} = \frac{10}{40}

\frac{5}{20} = \frac{1}{4}

\frac{1}{4} = \frac{1}{4}

This is a geometric sequence, in which:

The first term is 40, so a_{1} = 40

The common ratio is \frac{1}{4}, so r = \frac{1}{4}.

We have that:

a_{n} = a_{1}*r^{n-1}

The 10th term is a_{10}. So:

a_{10} = a_{1}*r^{9}

a_{10} = 40*(\frac{1}{4})^{9}

a_{10} = \frac{40}{262144}

Simplifying by 4, we have:

a_{10} = \frac{10}{65536}

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Answer:

Hi! The nswer to your question is m = 1

Step-by-step explanation:

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X over 8 = -5 . What is X?
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Step-by-step explanation:

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