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VMariaS [17]
3 years ago
14

Given: mTP= 70°,m∠EPT = 54° Find: Angles of △SPT

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

The Angles of △SPT are

m\angle STP=35\°  

m\angle SPT=126\°

m\angle PST=19\°

Step-by-step explanation:

step 1

Find the measure of angle PET

we know that

The inscribed angle is half that of the arc it comprises.

m\angle PET=\frac{1}{2}(arc\ PT)

substitute the given values

m\angle PET=\frac{1}{2}(70\°)

m\angle PET=35\°

step 2

Find the measure of angle PTE

we know that

The sum of internal angles of a triangle must be equal to 180 degrees

In the triangle PET

m\angle PET+m\angle EPT+m\angle PTE=180\°

substitute the given values

35\°+54\°+m\angle PTE=180\°

m\angle PTE=180\°-89\°=91\°

step 3

Find the measure of angle STP  

we know that

The inscribed angle is half that of the arc it comprises.

m\angle STP=\frac{1}{2}(arc\ TP)

substitute the given values

m\angle STP=\frac{1}{2}(70\°)=35\°

step 4

Find the measure of angle SPT

we know that

m\angle SPT+m\angle EPT=180\° ----> by supplementary angles

m\angle SPT+54\°=180\°

m\angle SPT=180\°-54\°=126\°

step 5

Find the measure of angle PST

we know that

The sum of internal angles of a triangle must be equal to 180 degrees

In the triangle SPT

m\angle STP+m\angle SPT+m\angle PST=180\°

substitute the given values

35\°+126\°+m\angle PST=180\°

m\angle PST=180\°-161\°=19\°

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

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Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

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\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

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Step-by-step explanation:

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