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Pepsi [2]
2 years ago
15

Plzz help me with thsi quistion

Mathematics
2 answers:
Salsk061 [2.6K]2 years ago
8 0

Answer:

98 ft

Step-by-step explanation:

14x7

=98 ft

Roman55 [17]2 years ago
3 0

Answer:

98 ft

Step-by-step explanation:

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Really need help :( struggling
Scorpion4ik [409]

Answer:

B

Step-by-step explanation:

The original amount will be the coefficient of (1 + 0.04)^r which is $728.00.

6 0
3 years ago
Solve a = b - 4/ c for b.
ahrayia [7]

Answer:

ac + 4 = b

Step-by-step explanation:

Step 1: Write equation

a = (b - 4)/c

Step 2: Multiply both sides by <em>c</em>

ac = b - 4

Step 3: Add 4 on both sides

ac + 4 = b

6 0
3 years ago
Read 2 more answers
X-5y=55 slope intercept form
Talja [164]

Answer:

y = x/5 -11

Step-by-step explanation:

y = mx + b (slope intercept form)

5y = x-55

y = x/5 -11

4 0
3 years ago
Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in \frac{6}{5} hr

Pump A and C can fill tank in \frac{3}{2} hr

Pump B and C can fill tank in 2 hr

Let A be the total hr taken A therefore rate of A=\frac{1}{A} /hr

Let B be the total hr taken B therefore rate of B=\frac{1}{B} /hr

Let C be the total hr taken C therefore rate of C=\frac{1}{C} /hr

\frac{1}{A}+\frac{1}{B}=\frac{5}{6}-----1

\frac{1}{B}+\frac{1}{C}=\frac{1}{2}-----2

\frac{1}{A}+\frac{1}{C}=\frac{2}{3}-----3

Adding 1,2 & 3

2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1

thus time taken by A,B and C combined is 1 hr

7 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
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