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2 years ago

Is it a function? {(3,2),(0,1),(-2,1),(3,-2)}

Mathematics

2 answers:

11111nata11111 [884]2 years ago

5 0

Answer:

Step-by-step explanation:

to know if it is a function or not look at the x coordinate if any of the x coordinates repeat then its not a function but of any of the x coordinates don't repeat than it is a function

tatuchka [14]2 years ago

3 0

Answer:

Step-by-step explanation:

For it to be a function, every X value needs to have only 1 y value associated with it. This is not a function because x=3 has 2 y values:

(3, 2) and (3, -2)

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IF U SMART I WANNA SEE U ANSWER THIS Q! 11ponits?

olchik [2.2K]

Answer is 1.6 pounds

.02 is not big enough to round up, so round down

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2 years ago

A car travels 258 miles in 312 minutes at a constant speed. Which equation represents the distance, d, that the car travels in m

pashok25 [27]

Answer:

0.83 miles per minute

Step-by-step explanation:

The speed of the car can be found by dividing the distance by the time. THe distance is 258 miles and the time is 312 minutes.

$s=\frac{d}{t} \\s=\frac{258}{312} \\s=0.83$

6 0

2 years ago

How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y

son4ous [18]

Solution:

Given:

$x^2=6y$

Part A:

The vertex of an up-down facing parabola of the form;

$\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}$

Rewriting the equation given;

$\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\ \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\ \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\ \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\ \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}$

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

$\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}$

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

$\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}$

Therefore, the focus is;

$(0,\frac{3}{2})$

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

$\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}$

Therefore, the directrix is;

$y=-\frac{3}{2}$

3 0

5 months ago

The ratio of daisies to roses in a garden is 20:1. Does this garden have more roses or more daises in the garden

PtichkaEL [24]

Answer:

daisies

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Y = -2x + 2 y = 5x + 9

WITCHER [35]

X=-1 y=4 hope it helps

8 0

2 years ago