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4 years ago

Is it a function? {(3,2),(0,1),(-2,1),(3,-2)}

Mathematics

2 answers:

11111nata11111 [884]4 years ago

5 0

Answer:

Step-by-step explanation:

to know if it is a function or not look at the x coordinate if any of the x coordinates repeat then its not a function but of any of the x coordinates don't repeat than it is a function

tatuchka [14]4 years ago

3 0

Answer:

Step-by-step explanation:

For it to be a function, every X value needs to have only 1 y value associated with it. This is not a function because x=3 has 2 y values:

(3, 2) and (3, -2)

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masya89 [10]

Vete a la aplicación “SnapCal” y te dará todos los pasos y también las respuestas.

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3 years ago

Y = -1/2x - 4 Identify the y intercept Find the slope: 3x = 13 - y

il63 [147K]

Answer:i think its 0

Step-by-step explanation:

5 0

3 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

How do you identify if the equation is linear, exponential, or quadratic?

Naddika [18.5K]

Answer:

It's form. Linear is a normal line, exponential is a curvy line, and quadratic is a u shape with the vertice on the y-axis line, making half of the u on the left quadrant and the other half on the right quadrant

Step-by-step explanation:

first is linear, second is exponential and third is quadratic

8 0

4 years ago

Read 2 more answers

3,600 The square roots are and

ehidna [41]

Answer:

Step-by-step explanation:

60x60=3,600

6 0

3 years ago