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ella [17]
3 years ago
13

What is the next number in the pattern? 7,11,10,14,13

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0
I think the answer is 17 because the pattern adds 4 then takes away 1 so 14-1=13 13+4=17
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3 years ago
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The perimeters of the square and the triangle shown below are equal. What is the value of x?
Rudiy27
Perimeter is the sum of all the sides. So we can set up an equation:

\sf 3x+1+3x+1+3x+1+3x+1=2x+8+x+8+4x+2

Now solve for 'x', combine like terms:

When it comes to terms with variables it's just like normal addition but we keep the variable:

\sf 3x+3x+3x+3x=12x
\sf 2x+x+4x=7x

So we have:

\sf 12x+1+1+1+1=7x+8+8+2

Add:

\sf 12x+4=7x+18

Subtract 7x to both sides:

\sf 5x+4=18

Subtract 4 to both sides:

\sf 5x=14

Divide 5 to both sides:

\boxed{\sf x=2.8}
8 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
What value of x makes the equation true?<br> 3(4x-5)-4x+1=-6<br> Please show work
V125BC [204]

Answer:

x = 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

3(4x - 5) - 4x + 1 = -6

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute 3:                    12x - 15 - 4x + 1 = -6
  2. Combine like terms:       8x - 14 = -6
  3. Isolate <em>x</em> term:                 8x = 8
  4. Isolate <em>x</em>:                          x = 1

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    3(4(1) - 5) - 4(1) + 1 = -6
  2. Multiply:                               3(4 - 5) - 4 + 1 = -6
  3. Subtract:                              3(-1) - 4 + 1 = -6
  4. Multiply:                               -3 - 4 + 1 = -6
  5. Subtract:                              -7 + 1 = -6
  6. Add:                                     -6 = -6

Here we see that -6 does indeed equal -6.

∴ x = 1 is the solution to the equation.

3 0
3 years ago
Simplify: (16-5)-9 x 1 A. 5 B. 2 C. 4 D. 3
Mariulka [41]

Answer:

B it right...

Step-by-step explanation:

4 0
3 years ago
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