The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.
- <em>The linear equation of the function is: </em>
<em>.</em> - <em>The inverse function is: </em>
<em>
.</em> - <em>A practical domain is from 0% to 100%</em>
- <em>A practical range is from 7 to 29.9
</em>
<u>A. Input quantity</u>
The input quantity is the percentage of frozen citrus crop
<u />
<u>B. Output quantity
</u>
The output quantity is the cost of box of oranges
<u>C. The linear function</u>
We have:

<em>Calculate the slope of the function</em>




<em>The linear equation is calculated as follows:</em>



<u>D. Rewrite as y = mx + b</u>
We have:

Collect like terms


<em>The function is:</em>

<u>E. A practical domain</u>
The domain is the possible values of P. Because P is a percentage, its possible values are 0% to 100%.
The domain of the function is: ![[0\%,100\%]](https://tex.z-dn.net/?f=%5B0%5C%25%2C100%5C%25%5D)
<u>F. A practical range</u>
When P = 0%

When P = 100%
Hence, the range of the function is: ![[7,29.9]](https://tex.z-dn.net/?f=%5B7%2C29.9%5D)
G. The meaning of 
The inverse function of g(P) is 
So:
is the percentage of frozen citrus crop, when the cost is $12.
<u>H. The inverse formula</u>
We have:

Subtract 7 from both sides

Make P the subject

So, the inverse formula is:

Substitute 12 for c



Read more about linear equations at:
brainly.com/question/19770987