let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
1. b=39.497
2. c=3.606
3. a=18.974
Step-by-step explanation:
1.
41^2-11^2=b^2
1681-121=b^2
b^=1560
b=39.497
2.
2^2+3^2=c^2
4+9=c^2
c^2=13
c=3.606
3.
21^2-9^9=a^2
441-81=a^2
a^2=360
a=18.974
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25 hours, 8 computers in 1 hour, take 200 computers and divide by 8 to find hours
