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lidiya [134]
3 years ago
5

If (t+10)+t=t+20, what is the value of t?

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0

Answer:

t=10

Step-by-step explanation:

(t+10)+t=t+20,

Combine like terms

2t+10 = t+20

Subtract t from each side

2t-t+10 =t-t+20

t+10 =20

Subtract 10 from each side

t+10-10 = 20-10

t = 10

Lady bird [3.3K]3 years ago
6 0

Answer:

t = 10

Step-by-step explanation:

2t+10 = t+20

-t          -t

__________

t + 10 = 20

   -10   -10

_________

t         = 10

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m=-\frac{7600}{8250}=-0.921

Nowe we can find the means for x and y like this:

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Step-by-step explanation:

For this case we have the following data given:

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Price (y): 141 , 133,126, 128,113,97, 90, 82,79,53

We want to construct a linear model like this:

y = mx +b

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i =550

\sum_{i=1}^n y_i =1042

\sum_{i=1}^n x^2_i =38500

\sum_{i=1}^n y^2_i =115882

\sum_{i=1}^n x_i y_i =49710

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=38500-\frac{550^2}{10}=8250

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=49710-\frac{550*1042}{10}=-7600

And the slope would be:

m=-\frac{7600}{8250}=-0.921

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{550}{10}=55

\bar y= \frac{\sum y_i}{n}=\frac{1042}{10}=104.2

And we can find the intercept using this:

b=\bar y -m \bar x=104.2-(-0.921*55)=104.707

So the line would be given by:

p(x)=-0.921 x +104.707

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