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OLEGan [10]
3 years ago
13

What's the answer and how do you do it?

Mathematics
2 answers:
stepan [7]3 years ago
8 0

This question is not easy. You have to make up some sort of numbering system to it.

red blue green green1 yellow purple

1.......2.......3...........4............5...........6 and then it repeats.

So the first step is to figure out what the 16th color was. We will need real help if it is green or green one. Unfortunately, I think it was. The 12th one was purple.

13 = red

14 = blue

15 = green

16 = green 1

The new 16th one is blue. So we have to find out what will make the 16th one blue. There are still six colors The new fourth one has to be blue. You have to start with yellow

yellow purple red blue green green1.

1.......2.......3...........4............5...........6

Enough loops were cut off so that the new starting point is yellow. That would mean we cut off red blue green green 1

We need the closest number to 51 that is divisible by 6. That would be 48. There will be 3 loops left over. The new 48th loop will be green1 (see above)

The 49th loop will be yellow

The 50th loop will be purple

The 51st loop will be RED <<<<< Answer

Leona [35]3 years ago
4 0

The 51st loop is 35 loops after the 16th loop. We know the sequence repeats every 6 loops, so this will be the same as the 5th loop after the blue one in the sequence beginning with blue. That sequence is

... blue, green, green, yellow, purple, red

and the 5th loop after the blue one is red.

The 51st loop will be red.

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B, x=1

Explanation
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A box contains 144 marbles, which are either red or blue. if there are 3 times as many red marbles as there are blue marbles in
kicyunya [14]
Given:
X: The blue marbles.
3X: The red marbles.
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SOLVING:
X + 3X = 144
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X = \frac{144}{4}
X = 36 ===> The blue marbles.

If there are 3 times as many red marbles as there are blue marbles:
3(36) = 108 ===> The red marbles. SOLUTION

TESTING:
36+108=144
\boxed{144}=\boxed{144}\quad\checkmark\ The\ value\ is\ correct.
GOOD LUCK...!!!
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Answer:

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