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kykrilka [37]
3 years ago
9

Find the first derivative?

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
You could do the question the way it is  written, but it is far easier to bring the negative power up to the numerator.

y= x^2 - 3. The derivative of that is
dy/dx = 2x The three is a constant and is always dropped when a derivative is taken
d(-3)/dx = 0

If you are a purist and want to solve the question the way it is written, you could do it this way.

dy/dx = d(1)/dx x^-2 - d(x^-2)/dx * 1
             ======================                    
                          (x^-2)^2

dy/dx =  - (-2 x^ - 3) / x^-4

dy/dx = 2 x^-3 * x^4
dy/dx = 2 x^(-3 + 4)
dy/dx = 2x ^ 1
dy/dx = 2x <<<<< answer
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The science club and the French club both ordered pizzas for their end-of-year banquets. After the banquets, the science club ha
tankabanditka [31]

Answer:

A. 23/24

Hope this helped

Step-by-step explanation:

6 0
3 years ago
If 3t-7=5t, then 6t=?<br><br> Explain how you got your answer!
kirill [66]

Answer:

6t = -21

Step-by-step explanation:

3t-7 = 5t simplifies by subtracting 5t on both sides, then adding 7 on both sides:

3t -5t  -7 +7 = 5t-5t+7

-2t = 7

t = -7/2

Then 6t = 6*-7/2 = -21

6 0
3 years ago
Read 2 more answers
Courtney is twice as old as Andre and three years older than Natalie. Courtney is half Shari's age. The difference between Shari
lesantik [10]

The question does not seem complete, but I'll represent the statement mathematically and look for their ages each. This is because the worst they can ask for is their ages.

Let C stand for Courtney's age, A for Andrei's age, N for Natalie's age and S for Shari's age. From the question we can deduce the following:

C = 2A

C = N + 3

C = S/2

S - N = C + A

S = 2C, N = C - 3 and A = C/2, therefore we have

2C - (C - 3) = C + C/2

C + 3 = C + C/2

C/2 = 3 and C = 6

A = C/2

A= 6/2

A = 3

N = C - 3

N = 6 - 3

N = 3

S = 2C

S = 2 x 6

S = 12.

C = 6, A = 3, N = 3 and S = 12

8 0
3 years ago
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
3 years ago
Help!! I’ll give u Brainly ASAP!
timama [110]

Answer:

-2, 4

Step-by-step explanation:

basically just move the dot the same distance on the other side

7 0
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