<span><em />
3x+y=5</span>
<span /><span>2x-2y=22 ...............2(x-y)=22 ⇒ x-y=11</span><span><em /></span>
<span><em>3x+y=5</em></span>
<span /><span><em><u>x-y=11 </u> </em>(+)</span>
<span />3x+x+y-y=11+5
<span>4x=16 /:4</span>
<span /><em>x=4</em>
x-y=11
4-y=11
-y=7 /*(-1)
<em>y=-7</em>
<span><em></em></span>
Answer:
3x^2 + 3xy/2 - 7xy^2/2
Step-by-step explanation:
So we know the perimeter is 20x^2 + xy - 7y^2,
To find any perimeter you need 2l + 2w = P so,
One of the sides is 7x^2 - xy
First plug in the values,
2(7x^2-xy) + 2w = 20x^2 + xy - 7y^2
Multiply,
14x^2-2xy + 2w = 20x^2 + xy - 7y^2
Subtract,
14x^2 - 2xy - 14x^2 + 2xy + 2w = 20x^2 + xy - 7y^2 - 14x^2 + 2xy
2w = 6x^2 + 3xy - 7y^2
w = 3x^2 + 3xy/2 - 7xy^2/2
If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16.
Answer: y= sin x+2
Step-by-step explanation:
Answer:
The measure of the largest angle in the kite is 128 degrees
Step-by-step explanation:
we know that
The sum of the interior angles in any quadrilateral must be equal to 360 degrees
A kite is a quadrilateral
Let
A,B,C and D the measure of the interior angles
so
we have that
substitute
----> equation A
Remember that
one is four times larger than the other
so
----> equation B
substitute equation B in equation A
solve for D
Find the measure of angle C
therefore
The measure of the largest angle in the kite is 128 degrees
