Answer:
30. Y= ×(-3)+4
Step-by-step explanation:
-2(-3)=6+4=10
therefore 1(-3)+4
=1
2(-3)=-6
-6+4=-2
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
Answer:I think it’s a,c,e
Step-by-step explanation:
Angle K = angle M
(4x-1)=(2x+27)
4x-2x=27+1
2x=28
x=14
K=4x-1 then 4(14)-1
55 degrees
M=2x+27 then 2(14) +27
55 degrees
K+M+L =180
55+55+L=180
110+L=180
L=70 degrees
Therefore K=55 degrees M=55 degrees L=70 degrees
The parameter of a rectangle can be alculated using the following rule:
parameter = 2(length + width)
from the givens:
length = 13 inches
width = 10 inches
so, just substitute with the givens in the equation to calculate the parameter:
parameter = 2(10+13) = 2*23 = 46 inches
