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Stels [109]
3 years ago
7

Chelsea and Pedro manipulated the rational expression \dfrac{14k^3 + 7k^2}{7k^3 + 14k^2} 7k 3 +14k 2 14k 3 +7k 2 ​ start fractio

n, 14, k, cubed, plus, 7, k, squared, divided by, 7, k, cubed, plus, 14, k, squared, end fraction. Their responses are shown below.
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

Step-by-step explanation:

\frac{14k^3+7k^2}{7k^3+14k^2} =\frac{7k^2(2k+1)}{7k^2(k+2)} =\frac{2k+1}{k+2}}

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Step-by-step explanation:

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X-(-27)=35-12 solving equation
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What is 27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5 <br> Answer this fast please!
Dimas [21]

Answer:

86.16

Step-by-step explanation:

27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5

PEMDAS

Multiply and divide first

3/3 is 1   and 75/5 = 15

Replace these into the equation

27+1 +4-1+72.4-34.24+6-4+15

Then add and subtract from left to right

31 +72.4-34.24+6-4+15

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7 0
3 years ago
Read 2 more answers
Y-x=15 y-x=5 using elimination
Galina-37 [17]

Answer:

No solution

Step-by-step explanation:

To eliminate is to get rid of one of the variables.

You can choose to either add each term in the equations or subtract each term in the equation.

For a variable to be eliminated, there must one pair that have the same constant with it. Each equation already has the same constant with a variable.

Try adding them.

.     y - x = 15

<u>+    y - x = 5</u>

2y - 2x = 20   No variables were eliminated.

Try subtracting.

.     y - x = 15

<u>-     y - x = 5</u>

0y - 0x  = 10   All variables were eliminated.

.         0 = 10     This is false.

This system of equations cannot be solved.

Graphically, these two lines would have the same slope and are parallel. The solution to a system is same as the point of intersection. Parallel lines never meet, never intersect, therefore there is no solution.

3 0
3 years ago
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