(x^1/8 y^1/4 z^1/2)^8
(8 √x 4 √y √z^8)
(8 √x 8 √y^2 8 √z^4)^8
8 √xy^2z^4^8
Solution: xy^2 z^4
Answer:
![h(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
Step-by-step explanation:
we have
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
The inflection point of f(x) is the point 
The inflection point of h(x) is the point
-----> see the given graph
so
the rule of the translation of f(x) to h(x) is

That means------> The translation is
units to the left
therefore
The equation of h(x) is equal to
![h(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
Answer:
3 1/5
Step-by-step explanation:
Answer:
If I read this right
3 (n -12) + 14 = 4 (7 - 5n)
First, remove the parentheses
3 n - 36 + 14 = 28 - 20 n
Combining terms
23 n = 28 - 14 + 36 = 50
n = 50 / 23 = 2 4/23 = 2.17