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SSSSS [86.1K]
3 years ago
10

Caleb is selecting cards from a set of 12 cards numbered 1-2-4-4-5-5-5-5-6-9-10-13.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
0 0

1-2-4-4-5-5-5-5-6-9-10-13.

Step-by-step explanation:

it back ward

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Help Me out with this question plz thx​
SVEN [57.7K]

Answer:

6x³ - 8x + 9

Step-by-step explanation:

Step 1: Write out expression

2x + 7 + 6x³ - 1 + 3 - 6x - 4x

Step 2: Combine like terms (x)

6x³ - 8x + 7 - 1 + 3

Step 3: Combine like terms (constants)

6x³ - 8x + 9

5 0
3 years ago
Read 2 more answers
To get a 100 kilograms of a 48% fat content chocolate how many kilograms of a 30% and 50% mix should be used
wlad13 [49]
A kilogram %30 chocolate,
b kilogram %50 chocolate,
a+b = 100 kilogram chocolate,

48.(a+b) = 30.a + 50.b
48a + 48b = 30a + 50b
18a = 2b
b = 9a

a+b = a + 9a = 10a = 100 kg
a = 10 kg
b = 9.a = 90 kg

You should use,

10 kg %30 chocolate,
90 kg %50 chocolate
8 0
4 years ago
There are 60 flowers in a bouquet, 24 of which are yellow. What percent of the flowers are yellow?
Kobotan [32]

Answer:

40%

Step-by-step explanation:

6 0
3 years ago
A company is designing a new cylindrical water bottle. The volume of the bottle will be 149 cmcubed. The height of the water bot
Arlecino [84]

Answer:

2.33

Step-by-step explanation:

If you put the numbers into the radius formula you should end up with this number hope this helps:)

7 0
3 years ago
Use the empirical rule to solve the problem. The annual precipitation for one city is normally distributed with a mean of 288 in
nadezda [96]

Answer:

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

X \sim N(288,3.7)  

Where \mu=288 and \sigma=3.7

The confidence level is 95.44 and the signficance is 1-0.9544=0.0456 and the value of \alpha/2 =0.0228. And the critical value for this case is z = \pm 1.99

Using this condition we can find the limits

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

8 0
3 years ago
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