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Salsk061 [2.6K]
3 years ago
7

Dot lives 0.2 miles from school and Eleanor lives 0.5 miles away. Who has the longer walk to school each day??

Mathematics
1 answer:
anastassius [24]3 years ago
7 0
.2 is 2/10 while .5 is 1/2.  1/2 is much larger than 1/5 (which is 2/10 reduced).
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Write a multiplication problem in which the product has two decimal places
sukhopar [10]
.5 x .5 = .25

Here you go! :)
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Help ? Pls ???????? Don’t know
Anni [7]

Answer:

y=-3x+7

Step-by-step explanation:

y=mx+b is the formula you are going to end up once completed.

This, by given two points:

(4,-5) (3,-2)

\frac{-2-5}{3-4} = Point-Slope Intercept Form

\frac{3}{-1} = After subtracting both from above

-3 = is your slope, decreasing.

Substitute -3 for y=mx+b

y=-3x+b

Use one of the given points (any) to find what b equals.

(4,-5)

x    y

-5=-3(4)+b

-5= -12+b

7=b

Final Equation:

y=-3x+7

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What is the length of line AB? Given Line AB = 4x line BC = 2x + 6
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The answer to this is 16.
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Which of the following equals 140 to nearest 10
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<span>Which of the following equals 140 to nearest 10 
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B.145 

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3 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
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