Answer:
A. 4/8 + 2/4 =1 B.5/8 + 1/4 =0.875
C.6/8 + 3/4 =1.5 D.7/8 + 2/4 =1.375
<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
Hello!
Step-by-step explanation:
Mean: 48
Median: 40
Mode: None
Range: 63
Hope this helps!
Answer:
28, 30, 32
Step-by-step explanation:
Three consecutive even numbers are three even numbers that are next to each other. For example, 2, 4 and 6 would be 3 consecutive even numbers.
With this sort of problem, you want to try to let each number be equal to one thing and then construct the same number of equations as you have variables:
Let's let,
Integer 1 = X
Integer 2 = Y
Integer 3 = Z
X + Y + Z = 90
We also know, that
Y = X + 2
And that
Z = X + 4
Now, we can sub these equations into the first equation. We do this so that we have everything represented as the same variable.
90 = X + (X+2) + (X+4)
90 = 3X + 6
84 = 3X
28 = X
So, the numbers are 28, 30 and 32
Answer:
that is the solution
Step-by-step explanation:
it cannot be simplified
