If the vertical component is 29.6 m/s down, and the horizontal component
is 54.8 m/s parallel to the surface, then the magnitude of the slanty vector is
√(29.6² + 54.8²) = √(876.16 + 3003.04) = √3879.2 = 62.28 m/s .
That's 139 mph ! Wow !
Answer:
<em>Good Luck!</em>
Explanation:
Force applied by first student (F1) = 80 N
Force applied by the second student (F2) = 40 N
Displacement (d) = 10 m
Work done by first student (W1) = F1d = 80*10 = 800 J
Work done by second student (W2) = F2d = 40*10 = 400 J
Hence, the work done by the pushing student is 800 J and that by pulling student is
<h2> <u><em>400 J</em></u></h2>
Answer:
Newton's third law explains the generation of thrust by a rocket engine. In a rocket engine, hot exhaust gas is produced through the combustion of a fuel with an oxidizer. The hot exhaust gas flows through the rocket nozzle and is accelerated to the rear of the rocket. In re-action, a thrusting force is produced on the engine mount.
Explanation:
pa brainliest po :D
Answer:
The current through the wire is equal to 0.8 A.
Explanation:
Given that,
The length of a copper wire = 2 m
Potential difference = 24 mV
The current through the wire is 0.40 A.
The new potential difference is 48 mV.
We need to find the current through the wire.
As the potential difference is doubled for second wire. So the new current will be :
I' = 2I
= 2 × 0.4
= 0.80 A
So, the current through the wire is equal to 0.8 A.
Cutting and polishing exposed rock
